Answer:
26 yards
Step-by-step explanation:
The complete question is attached in the image below.
The distance between two points O([tex]x_1,y_1[/tex]) and P([tex]x_2,y_2[/tex]) is:
[tex]|OP|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
The location of the points of the polygon are as follows:
A(-5, 5), B(0. 5), C(4,2), D(1, -2), E(-2, -2), F(-5, 2). Therefore:
[tex]|AB|=\sqrt{(0-(-5))^2+(5-5)^2}=5\ yards \\\\|BC|=\sqrt{(4-0)^2+(2-5)^2}=5\ yards \\\\|CD|=\sqrt{(1-4)^2+(-2-2)^2}=5\ yards \\\\|DE|=\sqrt{(-2-1)^2+(-2-(-2))^2}=3\ yards\\ \\|EF|=\sqrt{(-5-(-2))^2+(2-(-2))^2}=5\ yards \\\\|FA|=\sqrt{(-5-(-5))^2+(2-5)^2}=3\ yards[/tex]
The perimeter of the fence = |AB| + |BC| + |CD| + |DE| + |EF| + |FA| = 5 + 5 + 5 + 3 + 5 + 3 = 26 yards.
