Answer:
1. 1:5
2. 3:10
3. 1:2
4. conservation of mass
Explanation:
1. a:b
weight of drug in outlet stream = 10%
weight of drug in stream containing the drug = 50%
we have 10% weight of a = 50% weight in b
a:b = 10:50
= 1/5 = 0.2
2. percentage of preservative in outlet = 3%
while preservative stream contains 10%
the ratio is 3:10 = 3/10
3. from 1 and 2,
ratio of drug to outlet is 1:5
ratio of preservative to outlet stream = 3:10
to get the answer to this question
1/5+3/10
=(2+3)/10
= 5/10
= 1/2 ratio of diluent
4. the basis of calculation is conservation of mass.