Respuesta :

onyebuchinnaji

Complete question:

A 50kg boy stands on a rough horizontal ground. The coefficient of static friction is .68. The present static friction between the boy and the ground is ?

Answer:

The present static friction between the boy and the ground is 333.2 N

Explanation:

Given;

mass of the boy, m = 50 kg

the coefficient of static friction, μ = 0.68

The static friction between the boy and the ground is given as;

[tex]F_s = \mu F_n\\\\F_s = \mu (mg)\\\\F_s = 0.68 *(50*9.8)\\\\F_s = 333.2 \ N[/tex]

Therefore,  the present static friction between the boy and the ground is 333.2 N

adioabiola

The complete question requires that we find the static friction between the boy and the horizontal ground.

Here, we are required to determine the static frictional force between the boy and the ground.

  • The static friction between the boy and the horizontal ground is; 333.2N

The coefficient of static friction is a measure of the frictional force between two objects or an object and a surface.

  • The coefficient of static friction is a measure of the frictional force between two objects or an object and a surface.The coefficient of static friction represented by the symbol, μ is given mathematically as;

μ = F(s)/F(n)

  • where F(n) is the normal reaction; in this case, the weight of the boy.

  • F(n) = 50 × 9.8

F(n) = 490N

Therefore, the static frictional force,

F(s) = μ × F(n)

  • F(s) = 0.68 × 490

F(s) = 333.2N.

Ultimately, the static friction between the boy and the horizontal ground is; 333.2N

Read more:

https://brainly.com/question/13758352

Otras preguntas