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John used an empty beaker with the mass of 53.126 g. In a separate jar, he had a mixture of salt and sand. He transferred two scoops of salt and sand mixture to the beaker. The overall mass was 65.449 g. As you know salt is soluble in water, he added enough water in the beaker with salt and sand mixture to completely dissolve the salt. He filtered the mixture and dried what was left in the filter. The mass of that residue was 8.200 g. Based on the experiment calculate the mass of salt, sand and the mixture (salt sand).

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sebassandin

Answer:

[tex]m_{mixture}=12.323g[/tex]

[tex]m_{sand}=8.200 g[/tex]

[tex]m_{salt}=4.123g[/tex]

Explanation:

Hello,

In this case, since the mass of the empty beaker is 53.126 g and with the mixture is 65.449 g, we can compute the mass of the whole mixture (water, sand and salt) via subtraction:

[tex]m_{mixture}=65.449g-53.126g=12.323g[/tex]

In such a way, since the residue obtained via filtration was sand only as it is not soluble in water, we infer that the mass of sand is 8.200 g:

[tex]m_{sand}=8.200 g[/tex]

Finally, since the mixture is composed by salt and sand, the mass of salt is:

[tex]m_{salt}=m_{mixture}-m_{sand}=12.323g-8.200g\\\\m_{salt}=4.123g[/tex]

Best regards.

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