Respuesta :
Answer:
t = √ 2y₀ / g
if they are at the same height, all the bullets must carry the target, since when advancing the height decreases
Explanation:
In this exercise we see that the bullets are fired horizontally so the time it takes to reach the ground is
y = y₀ + [tex]v_{oy}[/tex] t - ½ g t²
as they are fired horizontally their vertical velocity is zero and the height upon reaching the ground is zero y = 0
0 = y₀ - ½ g t²
t = √ 2y₀ / g
from here we can see that the time it takes for the bullets to hit the floor depends only on the initial height
Therefore, all the bullets that come out of the same height reach the ground at the same time, but at a different distance, so if one misses the target, everything must fail since reaching the target is below the initial height.
The horizontal distance traveled by the bullets is
x = v₀ₓ t
v₀ₓ =v₀
x = v₀ √2y₀/g
For a more precise calculation we should know the height of the target and the bullets, but if they are at the same height, all the bullets must carry the target, since when advancing the height decreases
