Assume that player one has 10 land cards in their deck and player two has 20. With what probability will each player have four lands in their hand? (b) Assume that player one has 10 land cards in their deck and player two has 20. With what probability will player one have two lands and player two have three lands in hand? (c) Assume that player one has 10 land cards in their deck and player two has 20. With what probability will player two have more lands in hand than player one?

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kalsoomtahir1 kalsoomtahir1 · Answer 1 · 2020-09-23T17:59:39+02:00

Answer and Explanation:

Total number of cards = n(s) = 30

Player one have 10 cards and player two have 20 cards.

Probability of each player having four land in their hand =?

Probability of having four cards = (probability of one player)(probability of 2nd player) / total number of cards

= (10C4) (20C4) / 30

(b) Total number of cards = n(s) = 30

Player one have 10 cards = P(A)

Player two have 20 cards= P(B)

Probability of having player one two cards and player two has three cards =?

= (10C2) (20 C3) / 30

(c) Total number of cards = n(s) = 30

Player one have 10 cards = P (A)

Player two have 20 cards= P (B)

Probability of having cards player two more than player one =?

P (B) = 20/30