Answer:
The value is [tex]k =66\%[/tex]
Explanation:
From the question we are told that
The mass of toluene [tex] m_t =0.73 \ g [/tex]
The mass of potassium permanganate is [tex] m =2.0 \ g [/tex]
The volume of potassium hydroxide V = 7.0 mL
The concentration of potassium hydroxide C = 6 M
The mass of benzoic acid is [tex]m_b = 0.633 \ g[/tex]
Generally the % yield of benzoic acid is mathematically represented as
[tex]k = \frac{m_b}{Z} * 100[/tex]
Here Z is the theoretical yield which is mathematically represented as
[tex]Z = \frac{E}{W} * m_t [/tex]
Here W is the molecular weight of product (benzoic acid) with value
W = 92.14 \ g
E is the molecular weight of reactant (toluene)with a constant value of
E = 122.12 g
So
[tex]Z = \frac{122.12 }{92.14} * 0.73 [/tex]
=> [tex]Z = 0.968 \ g [/tex]
So
[tex]k = \frac{0.633}{0.968} * 100[/tex]
=> [tex]k =66\%[/tex]
