what is an equation of the line that passes through the points (4,-6) and (8,-4)

Answer:
[tex]y = \frac{1}{2} x - 8[/tex]
Step-by-step explanation:
The equation of a line is usually written in the form of y=mx+c, where m is the gradient (also known as slope) and c is the y-intercept (the point through which the line cuts through the y-axis).
[tex]\boxed{gradient = \frac{y1 - y2}{x1 - x2} }[/tex]
Using the gradient formula above,
[tex]m = \frac{ -4 - ( - 6)}{8 - 4} \\ m = \frac{ - 4 + 6}{4} \\ m = \frac{2}{4} \\ m = \frac{1}{2} [/tex]
Substitute the value of m into the equation:
y= ½x +c
To find the value of c, substitute a pair of coordinates.
When x=4, y= -6,
-6= ½(4) +c
-6= 2 +c
c= -6 -2 (-2 on both sides)
c= -8 (simplify)
Thus, the equation of the line is y= ½x -8.