The sum of the ages of Jacob and Jasmine is 66 years. 6 years ago, Jacob's age was 2 times Jasmine's age. How old is Jacob now?

Respuesta :

27, first you take 66-12 bc that is both of their ages, and then I divided that by 2 since it’s twice jasmines age. Hope this helps and would appreciate a Brainly :)

Answer:

Jacob's age is 42

Jasmine's age is 24

Step-by-step explanation:

Let Jacob's age be x

Let Jasmine's age be y

x + y = 66

x - 6 = 2(y - 6)

x - 6 = 2y - 12

x - 2y = -12 + 6

x - 2y = -6

x + y = 66 ------- (1)

x - 2y = -6 ------- (2)

From (1),

x = 66 - y -------- (3)

Substitute the value of x in (2)

x - 2y = -6

66 - y - 2y = -6

-3y = -6 - 66

-3y = -72

y = -72/-3

y = 24

Solve for x in (1)

x + y = 66

x + 24 = 66

x = 66 - 24 = 42

x = 42, y = 24