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A car moving with constant acceleration covers the distance between two points 180 m apart in
6 sec. Its speed as it passes the second point is 45 m/s. What is its acceleration and its speed at the
first point.
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Respuesta :

Shakurr

distance = 180m

time = 6 secs

velocity = 45m/s

s= ut+ 1/2at²

2s=2ut+at²

2s-2ut= at²

2(180)-2(25)(6) =a(6)²

60=36a

1.66666 m/s² = a

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