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A physics student is sitting under a tree and observes an apple falling out of the tree. The student estimates that
the apple traveled 1.1 seconds straight down to the ground. Based on this information, what was the approximate
maximum velocity of the apple before it hit the ground?

Respuesta :

Answer:

v=10.78 m/s

Explanation:

Given that,

The student estimates that  the apple traveled 1.1 seconds straight down to the ground. We need to find the maximum velocity of the apple before it hit the ground. The initial velocity of the apple is equal to 0 as it was at rest. It will move under the action of gravity.

Using equation of motion to find it as follows :

v=u+at

a = g

⇒v=gt

v=(9.8 m/s²) × (1.1 s)

v = 10.78 m/s

So, the maximum velocity of the apple is 10.78 m/s.

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