jinjy0204
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PLEASE HELP!!!!!!
The mass of an electron is 9.109×10−31 kg, and the magnitude of the charge of an electron is 1.602×10−19 C. What is the ratio of the gravitational force to the electrostatic force between two electrons?(1 point)


3.233×10−23


2.390×10−43


3.093×1022


4.165×1042


Two identical particles have the same mass and the same charge. The mass of each particle is 3.346×10−27 kg. What is the charge on each particle if the ratio of the gravitational force to the electrostatic force is 1.619×10−36?(1 point)


2.266×10−19 C


4.413×1018 C


1.947×1037 C


5.135×10−38 C

Respuesta :

bellamuto

Answer:For this equation you would have to take the numerator and multiply with the other one, which would leave you with 24/80 and if you want the simplified version it would be 3/10, hope this helps! :)

Explanation:

onyebuchinnaji

The ratio of the gravitational force and electrostatic force is [tex]2.39 \times 10^{-43}[/tex].

The charge on each particle at the given force ratio is [tex]2.264\times 10^{-19} \ C[/tex].

The given parameters;

  • mass of the electron, m = 9.11 x 10⁻³¹ kg
  • charge of the electron, q = 1.602 x 10⁻¹⁹ C

The gravitational force on the electron is calculated as;

[tex]F_g = \frac{Gm^2}{r^2}[/tex]

The electrostatic force on the electron is calculated as;

[tex]F = \frac{kq^2}{r^2}[/tex]

The ratio of the gravitational force and electrostatic force is calculated as;

[tex]\frac{F_g}{F}= \frac{Gm^2}{r^2} \times \frac{r^2}{kq^2} = \frac{Gm^2}{kq^2} \\\\\frac{F_g}{F}= \frac{(6.67\times 10^{-11})\times (9.11\times 10^{-31})^2}{9\times 10^9 \times (1.602\times 10^{-19})^2} = 2.39 \times 10^{-43}[/tex]

The charge on each particle is calculated as follows;

[tex]\frac{Gm^2}{kq^2} = \frac{F_g}{F} \\\\\frac{(6.67\times 10^{-11}) \times (3.346\times 10^{-27})^2}{9\times 10^9 \times q^2} = 1.619\times10^{-36}\\\\q^2 = \frac{(6.67\times 10^{-11}) \times (3.346\times 10^{-27})^2}{9\times 10^9 \times 1.619\times10^{-36}}\\\\q^2 = 5.125 \times 10^{-38}\\\\q = \sqrt{5.125 \times 10^{-38}} \\\\q = 2.264 \times 10^{-19} \ C[/tex]

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