Given :
The ratio of the amount of gold to the amount of silver is 2:5.
To Find :
The weight of gold in the alloy, if there are 80 g of silver.
Solution :
Let, amount of gold is x.
So, the ratio of amount of gold and silver is :
[tex]\dfrac{x}{80}=\dfrac{2}{5}\\\\x=32\ g[/tex]
Therefore, the weight of gold in the alloy is 32 g.
Hence, this is the required solution.
