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In many locations, old abandoned stone quarries have become filled with water once excavating has been completed. While standing on a 10.0 m high quarry wall, Clarence tosses a piece of granite into the water below. If Clarence throws the rock horizontally with a velocity of 3.0 m/s how far out from the edge of the cliff will it hit the water?

Respuesta :

abidemiokin

Answer:

Explanation:

Let us calculate the time of flight first using the formula;

Velocity = Displacement/Time

Time = Displacement/speed

Time = 10.0/3

Time = 3.33secs

Next is to calculate how far out from the edge of the cliff it will hit the water. To get that, we will use the equation of motion;

S= ut+1/2gt²

u is the initial velocity = 0m/s

g is the acceleration due to gravity = 9.81m/s

S = 0 + 1/2(9.81)(3.33)²

S = 4.905*3.33*3.33

S = 54.39m

Hence it will hit the water at 54.39m from the edge of the cliff

okpalawalter8

Answer:

  • It will hit the water at [tex]4.28m[/tex] off the cliff

Explanation:

Applying kinematic relations along vertical direction

[tex]y = V_0t + \frac{1}{2}a_yt^2[/tex]

where,

[tex]a_y = g[/tex]

therefore,

[tex]y = 0 + \frac{1}{2}gt^2[/tex]

The time taken

[tex]t = \sqrt{\frac{2y}{g}}\\\\t = \sqrt{\frac{2*10}{9.8}}\\\\t = 1.428s[/tex]

The horizontal distance

[tex]x = V_yt\\\\x = 3*1.428\\\\x = 4.28m\\\\[/tex]

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