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DragonPup315

Answer:

2.5cm

Step-by-step explanation:

If Luke's scale for his drawing is 5m to 2cm, then it means that every 2cm on Luke's scale drawing represents 5m in real life. So since the width of the fountain is 2cm, the actual fountain width must be 5m. As established in the example, Isabella's scale factor from drawing to real life is 6/3=2, which means any measurement in cm on her drawing can simply be multiplied by 2 to obtain the real life measurement in m. So, to convert back the other way, from real-life to drawing, we just need to divide the value by 2 instead of multiply. So, if the real life value is 5m, then the width on her scale drawing should be 5/2 = 2.5cm.

Hope this helped!

Using proportions, it is found that:

The width of the fountain in Isabella's scale drawing is of 1.6 cm.

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This question is solved by proportions, using a rule of three.

  • Isabella's scale is of 6m to 3cm, that is, 2m to 1cm.
  • Luke' scale is of 5 m to 2 cm, that is, 2.5m to 1 cm.
  • From this, it can be taken that a drawing of 250cm in Luke's scale is of 200 cm in Isabella's scale.
  • What is the width of Isabella's drawing, considering that Luke's width is 2 cm?

200 cm - 250 cm

x cm - 2 cm

Applying cross multiplication:

[tex]250x = 400[/tex]

[tex]x = \frac{400}{250}[/tex]

[tex]x = 1.6[/tex]

The width of the fountain in Isabella's scale drawing is of 1.6 cm.

A similar problem is given at https://brainly.com/question/23536327

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