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A student has a displacement of 304 m north in 180 s. What was the student's average velocity?
Given : Unknown: Equation: Substitution: Solve:

Subject is Physics

Respuesta :

Answer:

v = 1.69 m/s

Explanation:

Given that,

Displacement of the student is 304 m due North and it takes 180 s.

We need to find the student's average velocity. Using formula of velocity.

Velocity = displacement/time

[tex]v=\dfrac{304\ m}{180\ s}\\\\v=1.69\ m/s[/tex]

Hence, the student's average velocity is 1.69 m/s.

The student's average velocity will be "1.69 m/s".

Displacement and Velocity:

The main distinction between velocity as well as speed would be that velocity, like speed, seems to have a direction and therefore it is a vector quantity.

This same distance travelled together along a straight line throughout a particular direction from either the beginning point is defined as displacement. Because displacement has both size as well as the direction, it's a vector quantity.

Given values:

  • Displacement, d = 304 m
  • Time, t = 180 s

We know,

The velocity (v):

= [tex]\frac{Displacement}{Time}[/tex]

By substituting the values, we get

= [tex]\frac{304}{180}[/tex]

= [tex]1.69 \ m/s[/tex]

Thus the answer above is correct.

Find out more information about velocity here:

https://brainly.com/question/6504879

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