Volume of wheelbarrow , V = 2 1/2 ft³ = 5/2 ft³.
Volume of soil in wheelbarrow , [tex]v = \dfrac{5}{3}\ ft^3[/tex] .
Mass of soil in wheelbarrow , m = 75.25 pounds.
Now, volume left , [tex]v'=\dfrac{5}{6}\ ft^3[/tex] .
Let, mass of soil un wheelbarrow is x.
[tex]x=\dfrac{\dfrac{5}{6}\times 75.25}{\dfrac{5}{3}}\\\\x=37.625\ pounds[/tex]
Hence, this is the required solution.
