ruger has a dartboard with an area of 1600 cm^2. The dartborad has a circular bullseye centered at (0 cm, 0 cm). The point ( square root 3cm, square root 7cm) is on the circumference of the bullseye.

Respuesta :

A percentage is given by dividing a given value by a total and multiplying the result by 100

The percentage of the dartboard occupied by the bullseye is approximately 1.963 %

Reason:

The given parameters are;

The area of the dartboard, A = 1,600 cm²

The location of the center of the bullseye = (0 cm, 0 cm)

The coordinates of a point on the circumference = (√3 cm, √7 cm)

Question: Possible question with regards to the given parameter; The percentage of the dartboard covered by the bullseye

Solution;

The radius of the bullseye, r = [tex]\sqrt{(\sqrt{3})^2 + (\sqrt{9})^2} = \sqrt{10}[/tex]

The area of the bullseye, [tex]A_b[/tex] = π· r² = π × [tex](\sqrt{10})^2[/tex] = 10·π

∴ The area of the bullseye, [tex]A_b[/tex] = 10·π cm²

The percentage area is given as follows;

[tex]Percentage \ area = \dfrac{A_b}{A} \times 100[/tex]

Therefore;

[tex]Percentage \ area \ occupies \ by \ bulleseye = \dfrac{10 \cdot \pi}{1,600} \times 100 \approx 1.963 \%[/tex]

The percentage of the dartboard occupied by the bullseye ≈ 1.963 %

Learn more about percentage area here:

https://brainly.com/question/11642822

Answer:

2%

Step-by-step explanation:

Should be Choice B