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A baseball leaves a pitcher's hand horizontally at a speed v. The distance to the batter is d. (Ignore the effect of air resistance.) (a) How long does the ball take to travel the first half of that distance

Respuesta :

MrRoyal

Answer:

[tex]Time = \frac{d}{2v}}[/tex]

Explanation:

Given

[tex]Speed = v[/tex]

[tex]Distance = d[/tex]

Required

Determine the time taken to travel half of the distance

Recall that

[tex]Speed = \frac{Distance}{Time}[/tex]

Make Time the subject

[tex]Time= \frac{Distance}{Speed}[/tex]

In this case:

[tex]Distance = \frac{1}{2}d[/tex]

[tex]Speed = v[/tex]

So:

[tex]Time= \frac{Distance}{Speed}[/tex]

[tex]Time = \frac{\frac{1}{2}d}{v}[/tex]

[tex]Time = \frac{1}{2}d}/v[/tex]

[tex]Time = \frac{1}{2}d} * \frac{1}{v}[/tex]

[tex]Time = \frac{d}{2}} * \frac{1}{v}[/tex]

[tex]Time = \frac{d}{2v}}[/tex]

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