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A flight attendant surveyed passengers on a flight about where they wouldprefer to sit. The results are shown in the table Aisle Window Total 8 12 Back 10 14 24 Front 4 Total 14 22 36 What is the probability that a passenger prefers to sit in the front of the plane and prefersS a window seat? ​

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1239387

Answer:

2/3 or two thirds

Step-by-step explanation:

MrRoyal

The probability that a passenger prefers to sit in the front of the plane and prefers a window seat is 1/3

From the table, we have the following parameters.

  • 12 passengers prefer to sit in the front of the plane and a window seat.
  • 36 passengers are surveyed in total.

So, the required probability is:

[tex]\mathbf{Pr = \frac{12}{36}}[/tex]

Divide the numerator and the denominator by 12

[tex]\mathbf{Pr = \frac{1}{3}}[/tex]

Hence, the probability is 1/3

Read more about probabilities at:

https://brainly.com/question/11234923

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