Find the area of rectangle $BCEF$ . Round the area to the nearest whole number, if necessary.

A trapezoid A B C D is plotted on a coordinate plane. A D represents the longer base and B C represents the shorter base. Vertex A lies at ordered pair negative 5 comma 4. Vertex B lies at ordered pair 0 comma 3. Vertex C lies at ordered pair 4 comma negative 1. Vertex D lies at ordered pair 4 comma negative 5. A line is drawn from vertex B and intersects line A D at point F plotted at ordered pair negative 2 comma 1. A line is drawn from vertex C and intersects the line A D at point E plotted at ordered pair 2 comma negative 3.

The area is
square units.

Respuesta :

The area of a rectangle is the product of its dimensions. The area of rectangle BCEF is 16 square units

Given that:

[tex]B = (0,3)[/tex]

[tex]C = (4,-1)[/tex]

[tex]E =(2,-3)[/tex]

[tex]F = (-2,1)[/tex]

Refer to attachment for the missing figure

The area of a rectangle is:

[tex]Area= Length \times Width[/tex]

The length of the rectangle can be represented as: BC or FE

The width of the rectangle can be represented as: BF or CE

The lengths of these sides can be calculated using distance formula

[tex]d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]

So, we have:

[tex]BC = \sqrt{(4- 0)^2 + (-1- 3)^2}[/tex]

[tex]BC = \sqrt{32}[/tex] ------ This represents length

[tex]BF = \sqrt{(-2- 0)^2 + (1- 3)^2}[/tex]

[tex]BF = \sqrt{8}[/tex] ---- This represents width

The area is:

[tex]Area= Length \times Width[/tex]

[tex]Area = BF \times BC[/tex]

[tex]Area = \sqrt{32} \times \sqrt{8}[/tex]

[tex]Area = \sqrt{32 \times 8}[/tex]

[tex]Area = \sqrt{256}[/tex]

[tex]Area = 16[/tex]

Hence, the area of the rectangle is 16 square units

Read more about area on a coordinate plane at;

https://brainly.com/question/3903921

Ver imagen MrRoyal