What is the surface area of the polyhedron? Show your reasoning.

Area of top triangle = [tex]\frac{b \cdot h}{2} = \frac{4 \cdot 3}{2} = \frac{12}{2} = 6[/tex]
Area of bottom triangle = Area of top triangle = [tex]6[/tex]
Area of left rectangle = [tex]l \cdot w = 6 \cdot 4 = 24[/tex]
Area of middle rectangle = [tex]l \cdot w = 6 \cdot 5 = 30[/tex]
Area of right rectangle = [tex]l \cdot w = 6 \cdot 3 = 18[/tex]
Area of polyhedron = top triangle + bottom triangle + left rectangle + middle rectangle + right rectangle = [tex]6 + 6 + 24 + 30 + 18 = 84[/tex]
Surface area the given polyhedron is equals to 84square units.
"Surface area is the total area of all the surfaces occupied by any three dimensional body."
Formula used
Area of right angled triangle = ( 1/2) × base ×height
Area of rectangle = length ×width
According to the question,
As per the given diagram,
Two right triangles with equal measurement
Base = 4units
height = 3 units
Hypotenuse = 5units
Substitute the value in the formula we get
Area of 1 right angled triangle = ( 1/ 2) × 4 × 3
= 6 square units
Therefore,
Area of 2 right angled triangle = 2 × 6
= 12 square units ___(1)
Rectangle 1
Length = 6units
width = 4 units
Area of rectangle 1 = 6 × 4
= 24 square units ___( 2)
Rectangle 2
Length = 6units
width = 5 units
Area of rectangle 2 = 6 × 5
= 30 square units _____(3)
Rectangle 3
Length = 6units
width = 3 units
Area of rectangle 3 = 6 × 3
= 18 square units ___( 4)
Add(1) ,(2) , (3) , and (4), we get
Surface area of the polyhedron = 12 +24 +30 +18
= 84 square units
Hence, surface area the given polyhedron is equals to 84square units.
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