1. A mountain climbing expedition establishes a base camp and two intermediate camps, A

and B. Camp A is 11,200 m east of and 3,200 m above base camp. Camp B is 8,400 m

east of and 1,700 m higher than Camp A. Determine the displacement between base camp

and Camp B.

Respuesta :

Answer:

Explanation:

The diagram showing the illustration of the question is shown on the first uploaded image

Here G represents the base

So the displacement in the x -axis is mathematically represented as

[tex]X = 11200 + 8400 = 19600 \ m[/tex]

The displacement in the y -axis is mathematically represented as

[tex]Y 3200 + 1700 = 4900 \ m[/tex]

Generally the resultant displacement is

[tex]R = \sqrt{ X^2 + Y^2}[/tex]

[tex]R = \sqrt{ 19600^2 + 4900^2}[/tex]

[tex]R = 20200\ m [/tex]

Generally the direction of this resultant displacement is mathematically represented as

[tex]\theta = tan ^{-1} [\frac{Y}{X} ][/tex]

=>       [tex]\theta  =  tan ^{-1} [\frac{4900}{19600} ][/tex]

=>            [tex]\theta  = 14.03 ^o  [/tex]

Hence the direction is  [tex]14.03 ^o[\tex] from the horizontal axis

 

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