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3. A Japanese bullet train slows from a speed of 50 m/sec to a speed of 40 m/sec in 500m.
What is its acceleration?

Respuesta :

MathPhys

Answer:

-0.9 m/s²

Explanation:

Given:

Δx = 500 m

v₀ = 50 m/s

v = 40 m/s

Find: a

v² = v₀² + 2aΔx

(40 m/s)² = (50 m/s)² + 2a (500 m)

a = -0.9 m/s²

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