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A projectile is fired from the origin (at y = 0 m) as shown in the diagram. The initial velocity
components are Vox = 310 m/s and Voy = 26 m/s. The projectile reaches maximum
height at point P, then it falls and strikes the ground at point Q, which is 20 m below the launch
point. When the projectile reaches point Q, what is the vertical component of its velocity?
-40 ms
-33 m/s
-26 m/s
-87 m/s
70 m's

A projectile is fired from the origin at y 0 m as shown in the diagram The initial velocity components are Vox 310 ms and Voy 26 ms The projectile reaches maxim class=

Respuesta :

sebassandin

Answer:

-26 m/s.

Explanation:

Hello,

In this case, since the vertical initial velocity is 26 m/s and the vertical final velocity is 0 m/s at P, we compute the time to reach P:

[tex]t=\frac{0m/s-26m/s}{-9.8m/s^2} =2.65s[/tex]

With which we compute the maximum height:

[tex]y=26m/s*2.65s-\frac{1}{2}*9.8m/s^2*(2.65s)^2 \\\\y=34.5m[/tex]

Therefore, the final velocity until the floor, assuming P as the starting point (Voy=0m/s), turns out:

[tex]v_f=\sqrt{0m/s-(-9.8m/s^2)*2*34.5m}\\ \\v_f=-26m/s[/tex]

Which is clearly negative since it the projectile is moving downwards the starting point.

Regards.

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