Step-by-step explanation:
Hey there!
Distance = 12x^2+11x+2.
And Time = 3x+2 hours.
Now;
[tex]speed = \frac{distance}{time} [/tex]
Put all values.
[tex]s = \frac{12 {x}^{2} + 11x + 2}{3x + 2} [/tex]
Use mid term factorization is numerator and simplify them to get answer.
[tex]s = \frac{12 {x}^{2} + (8 + 3) x+2 }{3x + 2} [/tex]
[tex]s = \frac{12 {x}^{2} + 8x + 3x + 2 }{3x + 2} [/tex]
[tex]s = \frac{4x(3x + 2) + 1(3x + 2)}{(3x + 2)} [/tex]
[tex]s = \frac{(4x + 1)(3x + 2)}{(3x + 2)} [/tex]
[tex]s = (4x + 1)[/tex]
Therefore the speed is (4x+1)/hr.
Hope it helps..
