Answer:
[tex]x=7[/tex]
Step-by-step explanation:
[tex]\frac{2}{5}x+\frac{1}{3}=\frac{1}{3}x+\frac{4}{5}[/tex]
Subtract [tex]\frac{1}{3}[/tex] from both sides:
[tex]\frac{2}{5}x+\frac{1}{3}-\frac{1}{3}=\frac{1}{3}x+\frac{4}{5}-\frac{1}{3}[/tex]
[tex]\frac{2}{5} x=\frac{1}{3}x+\frac{12}{15}-\frac{5}{15}[/tex]
[tex]\frac{2}{5}x=\frac{1}{3}x+\frac{7}{15}[/tex]
Subtract [tex]\frac{1}{3} x[/tex] from both sides:
[tex]\frac{2}{5}x-\frac{1}{3}x=\frac{1}{3}x+\frac{7}{15}-\frac{1}{3}x[/tex]
[tex]\frac{6}{15}x-\frac{5}{15}x=\frac{7}{15}[/tex]
[tex]\frac{1}{15}x=\frac{7}{15}[/tex]
Multiply both sides by 15:
[tex]15\times \frac{1}{15}x=\frac{7\times 15}{15}[/tex]
[tex]x=\frac{105}{15}[/tex]
[tex]x=7[/tex]
