Answer:
37.5m/s
Step-by-step explanation:
If a coal train in Montana starts from rest and accelerates at 2.5 m/s2 for 15s,let us calculate the final velocity of the train.
Use the equation of motion v = u + at where;
v is the final velocity
u is the initial velocity = 0m/s (starts from rest)
a is the acceleration = 2.5m/s²
t is the time = 15secs
Substituting the given parameters into the formula;
v = 0+(2.5)(15)
v = 0+37.5
v = 37.5m/s
Hence the final velocity of the train is 37.5m/s
