Answer:
The distance traveled by the train is 691.2 m
Explanation:
Given;
initial velocity of the train, u = 32.9 m/s
deceleration of the train, a = - 0.783 m/s²
final velocity of the train when brought to a stop, v = 0
The distance traveled by the train is given by;
v² = u² + 2as
0 = (32.9)² + 2(-0.783)s
0 = 1082.41 - 1.566s
1.566s = 1082.41
s = 1082.41 / 1.566
s = 691.2 m
Therefore, the distance traveled by the train is 691.2 m
