A car traveling 29 mi/h accelerates uniformly for 8.5 s, covering 471 ft in this time.What was its acceleration? Round your answer to the nearest 100th place.Answer in units of ft/s.

Respuesta :

Explanation:

We know that :

u = 29 mph = 12.96 m/s

S = 471 ft = 143.5 m

t = 8.5 sec

[tex]s = ut + \frac{1}{2} a {t}^{2} [/tex]

143.5 = 12.96 * 8.5 + 1/2 * a * 72.25

a = 66.68 / 72.25

a (Acceleration) = 0.92 m/sec^2

= 3.01 ft/sec^2