Answer:
Step-by-step explanation:
eq. of circle is x²+y²+2gx+2fy+c=0
center=(-g,-k)
given eq. is x²+y²+4x-8y+11=0
comparing
2gx=4x
g=2
2fy=-8y
f=-4
center=(-2,4)
The required centre of the circle with equation x²+y²+4x-8y + 12will be at (-2,4)
The standard equation of circle is expressed as:
x^2+y^2+2gx+2fy+c = 0
where (-g, -f) is the centre of the circle
Given the equation x^2 + y^2 + 4x – 8y + 12 = 0
Compare with the general to have;
2gx = 4x
g = 2
2fy = -8y
y = -4
Since the centre is at (-g, -f), hence the required centre will be at (-2,4)
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