Respuesta :
The dog pen is most likely a rectangle. Area of a rectangle = length * width
a) possible dimension
150 / 5 = 30 ; length = 30 ; width = 5
150 / 7.5 = 20 ; length = 20 ; width = 7.5
150 / 10 = 15 ; length = 15 ; width = 10
150/ 12.5 = 12 ; length = 12.5 ; width = 10
b) maximum amount of fence. Compute for the perimeter.
P = 2(30 + 5) = 2(35) = 70
P = 2(20 + 7.5) = 2(27.5) = 55
P = 2(15 + 10) = 2(35) = 70
P = 2(12.5 + 12) = 2(24.5) = 49
MAXIMUM AMOUNT OF FENCE REQUIRED IS 70 FEET.
c) either: 30 by 5 or 15 by 10 dimension.
a) possible dimension
150 / 5 = 30 ; length = 30 ; width = 5
150 / 7.5 = 20 ; length = 20 ; width = 7.5
150 / 10 = 15 ; length = 15 ; width = 10
150/ 12.5 = 12 ; length = 12.5 ; width = 10
b) maximum amount of fence. Compute for the perimeter.
P = 2(30 + 5) = 2(35) = 70
P = 2(20 + 7.5) = 2(27.5) = 55
P = 2(15 + 10) = 2(35) = 70
P = 2(12.5 + 12) = 2(24.5) = 49
MAXIMUM AMOUNT OF FENCE REQUIRED IS 70 FEET.
c) either: 30 by 5 or 15 by 10 dimension.