Respuesta :
The number of situps form an AP with first term (a) = 17 and common difference (d) = 4
Tn = a + (n - 1)d
T12 = 17 + (12 - 1) x 4 = 17 + 11(4) = 17 + 44 = 61
Therefore, she will do 61 situps on day 12.
Tn = a + (n - 1)d
T12 = 17 + (12 - 1) x 4 = 17 + 11(4) = 17 + 44 = 61
Therefore, she will do 61 situps on day 12.
If the first term is 17 and the common difference will be 4. Then the 12th term will be 61.
What is a sequence?
A sequence is a list of elements that have been ordered in a sequential manner, such that members come either before or after.
The table shows how the number of sit-ups marla does each day has changed over time.
At this rate, the number of sit-ups will she do on day 12 will be
The first term is 17 and the common difference will be 4. Then the 12th term will be
Tₓ = a + (x - 1)d
T₁₂ = 17 + (12 - 1)4
T₁₂ = 17 + 44
T₁₂ = 61
More about the sequence link is given below.
https://brainly.com/question/21961097
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