Respuesta :
[tex]a=\sqrt{c^2-b^2}=\sqrt{17^2-11^2}=\sqrt{289-121}=\sqrt{168}=12.96[/tex]
Given:
Right triangle.
a = ? ; b = 11 ; c = 17.
Pythagorean theorem.
a² + b² = c²
a² = c² - b²
a² = 17² - 11²
a² = 289 - 121
a² = 168
a = √168
a = 12.96 Choice D.
Right triangle.
a = ? ; b = 11 ; c = 17.
Pythagorean theorem.
a² + b² = c²
a² = c² - b²
a² = 17² - 11²
a² = 289 - 121
a² = 168
a = √168
a = 12.96 Choice D.