Respuesta :
So E u(seful) is 3200 J and E l(oss) is 8200 J. E t(otal) is thus 11400 J. For the efficiency you do E u/ E t so 3200/11 400= 0.28 or 28%
The efficiency of this engine is 28.07%.
Given information:
The heat produced (loss) by the engine is [tex]h_l=8200[/tex] J.
The useful work (work done) by the engine is [tex]W=3200[/tex] J.
By the conservation of energy, the total energy supplied by the engine will be,
[tex]H=h_l+W\\H=8200+3200\\H=11400\rm\; J[/tex]
Now, efficiency is the ratio of useful work and the total energy supplied by the engine.
So, the efficiency can be calculated as,
[tex]\eta=\dfrac{W}{H}\\\eta=\dfrac{3200}{11400}\\\eta=0.2807=28.07\%[/tex]
Therefore, the efficiency of this engine is 28.07%.
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https://brainly.com/question/2676954