TheFlashMan21
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Of the 1,000 students in a local college, 420 own brand X mobile phones and 580 own brand Y mobile phones. Of these students, 80 own both brands of mobile phones. Find the probability that a student chosen at random has a brand X mobile phone given that he has a brand Y mobile phone.

Respuesta :

JeanaShupp

Answer: [tex]\dfrac{4}{29}[/tex]

Step-by-step explanation:

We know that the formula to find the conditional probability of A given that B is given by :-

[tex]P(A|B)=\dfrac{P(A\cap B)}{P(B)}[/tex]

Let A be the event that students own mobile phones  of Brand X and B be the event that students own mobile phones  of Brand Y.

Then , [tex]P(A)=\dfrac{420}{1000}[/tex]

[tex]P(B)=\dfrac{580}{1000}[/tex]

[tex]P(A|B)=\dfrac{80}{1000}[/tex]

Then , the required probability will be:-

[tex]P(A|B)=\dfrac{\dfrac{80}{1000}}{\dfrac{580}{1000}}\\\\\\\Rightarrow P(A|B)=\dfrac{4}{29}[/tex]

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