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Odina walked down the hall at school from the cafeteria to
the band room, a distance of 100.0 m. A class of physics
students recorded and graphed her position every 2.0 s,
noting that she moved 2.6 m every 2.0 s. When was Odina
in the following positions?
a. 25.0 m from the cafeteria
b. 25.0 m from the band room
c. Create a graph showing Odina’s motion.

Respuesta :

I think no 1 not sure

Answer:

Explanation:

As we know that when graph is plotted with the position and time then it shows that it will move with uniform speed

So here it is moving 2.6 m in 2 s

so speed is given as

[tex]v = \frac{2.6}{2}[/tex]

[tex]v = 1.3 m/s[/tex]

Part a)

when she reach 25 m from cafeteria

time taken by her

[tex]t = \frac{d}{v}[/tex]

[tex]t = \frac{25}{1.3}[/tex]

[tex]t = 19.2 s[/tex]

Part b)

When she will reach 25 m from band room

then total distance moved from cafeteria is

[tex]d = 100 - 25 = 75m[/tex]

time taken by her

[tex]t = \frac{75}{1.3}[/tex]

[tex]t = 57.7 s[/tex]

Part c)

Since Odina is moving at constant speed

so the position time graph must be a straight line graph

Ver imagen aristocles

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