Respuesta :

Yipes
NaOH:
V=50mL=0,05L
Cm = 2M

n = Cm*V = 0,05L * 2M = 0,1mol

HCl         +    NaOH ⇒ NaCl + H₂O
1mol        :     1mol
0,1mol     :     0,1mol

HCl:

n = 0,1mol
Cm = 3,5M

        n             0,1mol
V=---------- =   -----------        ≈ 0,029dm³ = 29mL of 3,5M HCl
       Cm           3,5 mol/dm³

Answer: The volume of HCl required will be 28.57 mL.

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

[tex]n_1M_1V_1=n_2M_2V_2[/tex]

where,

[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is HCl

[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base which is NaOH

We are given:

[tex]n_1=1\\M_1=3.5M\\V_1=?mL\\n_2=1\\M_2=2M\\V_2=50mL[/tex]

Putting values in above equation, we get:

[tex]1\times 3.5\times V_1=1\times 2\times 50\\\\V_1=28.57mL[/tex]

Hence, the volume of HCl required will be 28.57 mL.

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