Respuesta :
Given:
circle inscribed in a square.
Side length of the square = diameter of the circle.
Let x side length and diameter.
Area of a square = x²
Area of a circle = πr²
r = radius ; half of the diameter. = x/2
Area of a circle = π * (x/2)² or π (x²/4)
Ratio of the area of the square to the area of the circle
x² : π(x²/4) or x² / πx²/4
x² * 4/πx² = 4/π
circle inscribed in a square.
Side length of the square = diameter of the circle.
Let x side length and diameter.
Area of a square = x²
Area of a circle = πr²
r = radius ; half of the diameter. = x/2
Area of a circle = π * (x/2)² or π (x²/4)
Ratio of the area of the square to the area of the circle
x² : π(x²/4) or x² / πx²/4
x² * 4/πx² = 4/π
The area of a circle with a diameter d is [tex] \frac{ \pi d^4}{4} [/tex] and the area of a square whose side is the diameter d of the circle is [tex]d^2[/tex].
The ratio of the area of a square to the area of a circle is
[tex]d^2 : \frac{ \pi d^2}{4} [/tex]
Since there is a common term on both sides, we cancel [tex]d^2[/tex] and get the final ratio of:
[tex]1: \frac{ \pi }{4} [/tex]
The ratio of the area of a square to the area of a circle is
[tex]d^2 : \frac{ \pi d^2}{4} [/tex]
Since there is a common term on both sides, we cancel [tex]d^2[/tex] and get the final ratio of:
[tex]1: \frac{ \pi }{4} [/tex]