Respuesta :

[tex]\frac{ 3-6-2 \sqrt{18} }{ -3 } = -3-6 \sqrt{2} /-3=1+2 \sqrt{2} [/tex]
You amplify with sqrt(3)-sqrt(6).
I hope that this is the answer that you were looking for and it has helped you.


Answer: The answer is [tex]-3+\dfrac{2}{3}\sqrt{18}.[/tex]

Step-by-step explanation:  The given expression is

[tex]E=\dfrac{\sqrt 3-\sqrt 6}{\sqrt 3+\sqrt 6}.[/tex]

we will be rationalising the given expression as follows:

[tex]E\\\\\\=\dfrac{\sqrt 3-\sqrt 6}{\sqrt 3+\sqrt 6}\\\\\\=\dfrac{(\sqrt 3-\sqrt 6)^2}{(\sqrt 3+\sqrt 6)(\sqrt 3-\sqrt 6)}\\\\\\=\dfrac{3-2\sqrt {18}+6}{3-6}\\\\\\=\dfrac{9-2\sqrt{18}}{-3}\\\\\\=-3+\dfrac{2}{3}\sqrt{18}.[/tex]

Thus, the answer is [tex]-3+\dfrac{2}{3}\sqrt{18}.[/tex]