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Which of the following is not a way to represent the solution of the inequality 2(x + 1) greater than or equal to 20?

A) x __>__ 9
B) 9_<__ x
C) A number line with a closed circle on 9 and shading to the left.
D ) A number line with a closed circle on 9 and shading to the right.

Respuesta :

[tex]2x+2 \geq 20 2x \geq 18 x \geq 9 9 \leq x[/tex] which  is the same with the one above

The answer to your question is C.A number line with a closed circle on 9 and shading to the left. I hope that this is the answer that you were looking for and it has helped you.
calculista

Answer:

option C

A number line with a closed circle on  [tex]9[/tex] and shading to the left

Step-by-step explanation:

we have

[tex]2(x+1)\geq 20[/tex]

solve for x

[tex]2x+2\geq 20[/tex]

Subtract [tex]2[/tex] both sides

[tex]2x+2-2\geq 20-2[/tex]

[tex]2x\geq 18[/tex]

Divide by [tex]2[/tex] both sides

[tex]x\geq 9[/tex] --------> is equivalent to [tex]9 \leq x[/tex]

The solution is the interval--------> [9,∞)

All real numbers greater than or equal to [tex]9[/tex]

A number line with a closed circle on  [tex]9[/tex] and shading to the right

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