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We will use the state equation for an ideal gas to determine the volume that the Hydrogen occupied. The equation is
pV = nRT; where p is pressure in pascals, V is volume in meters cubed, n is the number of moles present, R is the gas constant (value 8.314 J/K*mol) and T is the absolute temperature in Kelvins.
First we convert 1 atm to Pascals, which is 101325 Pascals
Next, the temperature is converted to Kelvin by adding 273; so 273K
Finally, we must compute n by dividing the mass of the Hydrogen gas by its Molecular mass of 2. We obtain 9000 moles of Hydrogen gas. Substituting into the equation after rearranging for V:
V = (9000 * 8.314 * 273)/101325
Volume of Hydrogen present is 201.6 meters cubed.
We will use the state equation for an ideal gas to determine the volume that the Hydrogen occupied. The equation is
pV = nRT; where p is pressure in pascals, V is volume in meters cubed, n is the number of moles present, R is the gas constant (value 8.314 J/K*mol) and T is the absolute temperature in Kelvins.
First we convert 1 atm to Pascals, which is 101325 Pascals
Next, the temperature is converted to Kelvin by adding 273; so 273K
Finally, we must compute n by dividing the mass of the Hydrogen gas by its Molecular mass of 2. We obtain 9000 moles of Hydrogen gas. Substituting into the equation after rearranging for V:
V = (9000 * 8.314 * 273)/101325
Volume of Hydrogen present is 201.6 meters cubed.
Formula is:
P V = n R T
n = m / M
P * V = m / M * R * T
P = 1 atm = 101,325 Pa ; m = 18,000 kg; M = 0,002 kg/mole;
R = 8.314 J /mole K; T = 0° C = 273 K;
101,325 Pa * V = 18,000 kg / 0.002 kg/mole * 8.314 J/mole K * 273 K
V = ( 9,000,000 * 8.314 * 273 ): 101,325
V = 201,603.7 m³
P V = n R T
n = m / M
P * V = m / M * R * T
P = 1 atm = 101,325 Pa ; m = 18,000 kg; M = 0,002 kg/mole;
R = 8.314 J /mole K; T = 0° C = 273 K;
101,325 Pa * V = 18,000 kg / 0.002 kg/mole * 8.314 J/mole K * 273 K
V = ( 9,000,000 * 8.314 * 273 ): 101,325
V = 201,603.7 m³