Consider the graph of the linear function h(x) = –6 + x. Which quadrant will the graph not go through and why?

a. Quadrant I, because the slope is negative and the y-intercept is positive
b. Quadrant II, because the slope is positive and the y-intercept is negative
c. Quadrant III, because the slope is negative and the y-intercept is positive
d. Quadrant IV, because the slope is positive and the y-intercept is negative

h ( x ) = - 6 + x
m = 1 ( the slope )
b = - 6 ( y - intercept )
x - intercept:
0 = - 6 + x
x = 6
The graph is going through Quadrants: I, II and IV.
Answer:
B ) Quadrant II, because the slope is positive and y-intercept is negative.

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scme1702 scme1702 · Answer 2 · 2016-10-05T20:10:34+02:00

If we look at the function, we realize that it is a linear one. It can also be expressed in the form
h(x) = x - 6
For simplicity.
Upon entering x = 0 to find the y-intercept (since we know that the value of x on the y intercept is 0) we see that the y-intercept is -6; thus, negative.
Next, we check the sign of the coefficient of x (which is 1 in this case) and we see that the slope is positive. Thus, when we make a quick sketch or imagine the graph, we see that the line will not pass through the second quadrant.
The answer is B.