A body of rotational inertia 1.0 kg m2 is acted upon by a torque of 2.0 Nm. The angular acceleration of the body will be

Respuesta :

Answer:

The angular acceleration is 2 rad/s².

Explanation:

Given that,

Rotational inertia = 1.0 kg m²

Torque = 2.0 Nm

We need to calculate the angular acceleration

Using formula of torque

[tex]\tau=I\alpha[/tex]

[tex]\alpha=\dfrac{\tau}{I}[/tex]

Where, I = moment of inertia

[tex]\tau[/tex] = torque

Put the value into the formula

[tex]\alpha=\dfrac{2.0}{1.0}[/tex]

[tex]\alpha=2\ rad/s^2[/tex]

Hence, The angular acceleration is 2 rad/s².