Maximum area = 2ab
from ellipse eqn
x^2 + 4y^2 = 49
(x+4y)^2= 49
underoot both sides
x + 4y = 7 ---eqn1
from
[tex] \frac{ {x}^{2} }{ {a}^{2} } + \frac{ {y}^{2} }{{b}^{2} } = 1[/tex]
(ab)^2 = (ax + by)^2
ab= ax + by
compare to eqn1
ab=7
then, area of the largest triangle will be 14 units.
i hope it's ryt
