Answer:
Answer: U = 4x^2 and V=y-1
factored : (4x^2+y-1)(4x^2-y+1
Step-by-step explanation:
The value of U and V are 4x² and (y-1) respectively and the factor of the expression is (4x² + (y-1)) and (4x² + (y+1)) option (C) is correct.
It is defined as the combination of constants and variables with mathematical operators.
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
We want to factor in the following expression:
16x⁴-(y-1)²
We can factor the expression as (U+V)(U-V) where U and V are either constant integers or single-variable expressions.
1) What are U and V?
2)Factor the expression.
We have an expression:
= 16x⁴-(y-1)²
or
= (4x²)²-(y-1)²
Using the identity:
a² - b² = (a + b)(a- b)
(4x²)²-(y-1)² = (4x² + (y-1))(4x² + (y+1))
The value of U = 4x²
V = (y-1)
The factor of the expression is:
(4x² + (y-1)) and (4x² + (y+1))
Thus, the value of U and V are 4x² and (y-1) respectively and the factor of the expression is (4x² + (y-1)) and (4x² + (y+1))
Learn more about the expression here:
brainly.com/question/14083225
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