Given:
S is between R and T. RS = 2x + 7, RT = 4x , and ST = 28.
To find:
The length of segment RT.
Solution:
It is given that S is between R and T. So, by segment addition property, we get
[tex]RS+ST=RT[/tex]
On substituting the values, we get
[tex](2x+7)+(28)=4x[/tex]
[tex]2x+35=4x[/tex]
Subtract 2x from both sides.
[tex]35=4x-2x[/tex]
[tex]35=2x[/tex]
Divide both sides by 2.
[tex]\dfrac{35}{2}=x[/tex]
[tex]x=17.5[/tex]
Now,
[tex]RT=4x[/tex]
[tex]RT=4(17.5)[/tex]
[tex]RT=70[/tex]
Therefore, the length of segment RT is 70 units.
