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Toy cars
1
11,
2
22, and
3
33 are launched horizontally with the trajectories shown below. Cars
1
11 and
2
22 are launched from a
15

m
15m15, start text, m, end text high cliff, while Car
3
33 is launched from a
30

m
30m30, start text, m, end text high cliff. We can ignore air friction.

Respuesta :

Answer:

tcar 1 = tcar 2< tcar 3

Explanation:

khan academy

Initial launch speed of the cars are in order as  Vcar 1 = Vcar 2< Vcar 3

What is speed?

The speed of any moving object is the ratio of the distance covered and the time taken to cover that distance.

Toy cars 1, 2 and 3 are launched horizontally with the trajectories shown below. Cars 1 and 2 are launched from a 15 m high cliff, while Car 3 is launched from a 30m high cliff. We can ignore air friction.

The velocity of the toy car 1 and 2 is

V1/2 = √2gh

Put the values, we get

V 1/2= √(2x 9.81x 15)

V1/2 = 17.16 m/s

The velocity of the toy car3 is

V3 = √2gh

Put the values, we get

V3 = √(2x 9.81x 30)

V3 = 24.26 m/s

Thus,  Vcar 1 = Vcar 2 < Vcar 3

Learn more about speed.

brainly.com/question/7359669

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