For each line, determine whether the slope is positive, negative, zero, or undefined.
Line 1
Line 2
Line 3
Line 4
O Positive
Negative
O Zero
O Undefined
O Positive
O Negative
O Zero
O Undefined
O Positive
O Negative
O Zero
O Undefined
O Positive
O Negative
O Zero
O Undefined

For each line determine whether the slope is positive negative zero or undefined Line 1 Line 2 Line 3 Line 4 O Positive Negative O Zero O Undefined O Positive O class=

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Answer:

1. Negative

2. Undefined

3. Positive

4. Zero

Step-by-step explanation:

just took notes on subject and know answer. 100% sure its right

  1. The slope of the LlNE 1 is negative
  2. For the vertical line, since the line is parallel to the y axis and the change in the x-value is zero, hence the slope of LINE  2 will be UNDEFINED
  3. The slope of LlNE 3 is positive
  4. For the horizontal line (fourth graph), since the line is parallel to the x-axis and the change in the y-value is zero, hence the slope of LINE  4 will be ZERO

The slope of a line is determined by its steepness.

The formula for calculating slope is expressed as;

[tex]\frac{\triangle y}{\triangle x} = \frac{y_2-y_1}{x_2-x_1}[/tex]

For the first graph, we can assume the coordinates (-1, 0) and (0, -2), the [tex]\frac{\triangle y}{\triangle x} = \frac{-2-0_1}{0-(-1)}\\\frac{\triangle y}{\triangle x} = \frac{-2}{1}\\\frac{\triangle y}{\triangle x} = -2\\\\[/tex]

Since the slope is -2 which is a negative value, hence the slope of LlNE 1 is negative

For the vertical line, since the line is parallel to the y axis and the change in the x-value is zero, hence the slope of  LINE  2 will be UNDEFINED

For the THIRD graph, we can assume the coordinates (2, 0) and (0, -2), the [tex]\frac{\triangle y}{\triangle x} = \frac{-2-0}{0-2}\\\frac{\triangle y}{\triangle x} = \frac{-2}{-2}\\\frac{\triangle y}{\triangle x} = 1\\\\[/tex]

Since the slope is 1 which is a negative value, hence the slope of LlNE 3 is positive

For the horizontal line (fourth graph), since the line is parallel to the x-axis and the change in the y-value is zero, hence the slope of LINE  4 will be ZERO

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