Answer:
a
[tex]N = 7.0 *10^{44} \ Ways [/tex]
b
[tex]U = 2.85 *10^{26}\ ways [/tex]
Step-by-step explanation:
From the question we are told that
The number of students are n = 100
The number of dormitories is k = 3
The capacity of the first dormitory is A = 25
The capacity of the second dormitory is B = 35
The capacity of the third dormitory is c = 40
Generally the number of way to fill the dormitory up is mathematically represented as
[tex]N = \frac{n!}{A! B!C!}[/tex]
=> [tex]N = \frac{100!}{25! 35! 40!}[/tex]
Here ! stands for factorial, so we will be making use of the factorial functionality in our calculators to evaluated the above equation
=> [tex]N = \frac{100!}{25! 35! 40!}[/tex]
[tex]N = \frac{9.332622* 10^{157}}{[1.551121* 10^{25}]* [1.0333148* 10^{40}] * [8.1591528*10^{47}]}[/tex]
[tex]N = 7.0 *10^{44} \ Ways [/tex]
From the question we are told that there are 50 men and 50 women and
A is all-men's dorm and B is all-women's dorm while C is co-ed
So
When A is filled , the number of men that will be remaining to fill dorm C is 50-25 = 25
While when B is filled the number of women that will be remaining to fill dorm C is 50-35 = 15
Generally the number of ways there to fill the dormitories is equivalent to the number of ways of selecting the 25 men and 35 women to fill dormitory A and B plus one more way which is filling dorm C with the remaining students this is mathematically represented as
[tex]U = ^{50}C_{35} * ^{50}C_{25} + 1[/tex]
Here C stands for combination hence we will be making use of the combination functionality in our calculators
[tex]U = 2.250829575* ^{12} * 1.264106064 * 10^{14} + 1[/tex]
=> [tex]U = 2.85 *10^{26}\ ways [/tex]
